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Directions for filling in the Tables
Tab. I Day I (e). The names are written out alphabetically, and paired as they stand. The victors are marked with asterisks.
Tab. II. Day I (e). As B has been beaten by A, A is entered as his 'superior'; C as D's superior; and so on.
Tab. I. Day II (m). We first pair together all the unbeaten, A,C,E,G, &c. Then those who have one superior, B,D,F,H, &c.
Tab. II. Day II (m). We first enter the actual superiors, C,G, &c. Then, since A has a superior C, and B has a superior A, we see that B has a virtual superior C; and so on. We then see that D has 3 superiors, and must be struck out; and so with H, &c.
Tab. I. Day II (e). We first pair together all the unbeaten, C,G, &c. Then all with one superior, A,E, &c.; but when we come to J,L, we find we have a common superior; so we pair J with P, and L with Q. This series ends with an odd one, g, who must therefore be paired with the first of those who have two superiors each, F,T, &c.
Tab. I. Day III (m). Here, in pairing those with one superior, we again end with an odd one, g, who must therefore be paired with the first of those with two superiors, viz. T. We end with an 'odd man', c.
Tab. II. Day III (m). The unbeaten are now reduced to one pair, M, f, who therefore will do nothing this afternoon, but will have a whole-day contest to-morrow.
Tab. I. Day III (e). Those who have one superior are C,J,L,R, all with a common superior M; and then V,a,g, all with a common superior f. We therefore pair C with V, and so on, leaving an odd one R, who must be paired with the only one who has two superiors, viz. c.
Tab. II. Day III (e). Enter as usual.
Tab. I. Day IV (m). We pair the 2 unbeaten, M,f, for their whole-day contest. Then those with one superior.
Tab. II. Day IV (m). M and f are still contending. V and g are struck out.
Tab. I Day IV (e). J and R must be paired together, though they have a common superior.
Tab. I. Day IV (e). M is First-prize-man.
Tab. I. Day V (m). R and f must be paired together, though they have a common superior. J is `odd man'.
Tab. II. Day V (m). R is now the only man with one superior, and is therefore Second-prize-man.
Tab. I. Day V (e). J and f contend for the Third prize.
If this Tournament were fought by the present method, the 4 Prize men would be C,M,V,f: f would get the 2nd prize, and C and V the 3rd and 4th: i.e. the 5th best man would get the 2nd prize, and the 14th and 11th best the other two.
Table I
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